areeshae34 areeshae34 21-04-2024 Mathematics Answered If[tex]y = \sqrt{5 + 2 \\ } [/tex]Then find[tex]y + 1 \div y = [/tex][tex]y - 1 \div y[/tex][tex]y { }^{2} + 1 \div y {}^{2} = [/tex]