According to the following reaction, what amount of Al₂S₃ remains when 20.00 g of Al₂S₃ and 2.00 g of H₂O are reacted? A few of the molar masses are as follows: Al₂S₃=150.17g/mol, H₂O=18.02g/mol.
Al₂S₃(s)+6H₂O(l)→2Al(OH)₃(s)+3H₂S(g)
a) 28.33 g
b) 14.00 g
c) 8.33 g
d) 19.78 g
e) 17.22 g