Using the equations
SrO (s) + CO₂ (g) → SrCO₃ (s) ∆H° = -234 kJ/mol
2 Sr(s) + O₂ (g) → 2 SrO (s) ∆H° = -1184 kJ/mol
CO₂ (g) → C(s) + O₂ (g) ∆H° = 394 kJ/mol

Determine the molar enthalpy (in kJ/mol) for the reaction
2 SrCO₃ (s) → 2 Sr (s) + 2 C(s) + 3 O₂ (g).