Answer: a = mB ⋅ g−μk ⋅ mA ⋅ g over mA mB ​ Substitute the known values and solve: a = (238kg⋅9.8m/s2 − 0.09950⋅150kg⋅9.8m/s2) 150kg 238kg ​ Calculate a to find the acceleration of the objects. Explanation: To find the acceleration of the objects, we'll set up an equation based on the forces involved. The net force acting on the system is the difference between the gravitational and frictional forces. Let's denote the acceleration as a. For object A (on the table): F friction, A =μk ⋅ mA ⋅ g where: μk is the coefficient of kinetic friction (0.09950), mA is the mass of object A (150 kg), g is the acceleration due to gravity (approximately 9.8 m/s²). For object B (hanging freely): F gravity, B = mB ⋅ g where: mB is the mass of object B (238 kg). The net force (Fnet) is the difference between the gravitational force on B and the frictional force on A: Fnet = Fgravity, B − friction, A Now, according to Newton's second law, the net force is also equal to the mass times acceleration (Fnet = mtotal ⋅ a), where mtotal is the total mass of the system. mtotal =mA mB So, mtotal ⋅ a = Fgravity, B − Ffriction, A (mA mB) ⋅ a = mB ⋅ g−μk ⋅ mA ⋅ g Now, we can solve for a: a = mB ⋅ g−μk ⋅ mA ⋅ g over mA mB ​ Substitute the known values and solve: a = (238kg⋅9.8m/s2 − 0.09950⋅150kg⋅9.8m/s2) 150kg 238kg ​ Calculate a to find the acceleration of the objects. rating answer section Answer rating0.0 (0 votes)