To determine the number of moles in 30.6 L of Al2O3, you need to follow these steps:
1. **Identify the molar volume of a substance at standard temperature and pressure (STP):** The molar volume of a gas at STP is approximately 22.4 L/mol.
2. **Calculate the number of moles in 30.6 L of Al2O3:** Since Al2O3 is not a gas and does not have a fixed molar volume at STP like gases do, we need to convert the volume (in liters) to moles using the molar volume concept for gases.
3. **Apply the concept of molar volume conversion:** Given that Al2O3 is not a gas, we cannot directly use the molar volume of gases at STP. Instead, we need to determine the molar mass of Al2O3 and then calculate the number of moles using the formula:
Moles = Volume (in liters) / Molar volume (in liters per mole)
4. **Find the molar mass of Al2O3:** Aluminum oxide (Al2O3) has a molar mass of approximately 101.96 g/mol.
5. **Calculate the number of moles:**
Moles = 30.6 L / (101.96 g/mol)
Moles ≈ 0.299 moles
Therefore, there are approximately 0.299 moles in 30.6 L of Al2O3.
