Given circle EE with diameter start overline, C, D, end overline CD and radius start overline, E, A, end overline EA . start overline, A, B, end overline AB is tangent to EE at AA. If E, C, equals, 5EC=5 and E, A, equals, 5EA=5, solve for A, DAD. Round your answer to the nearest tenth if necessary. If the answer cannot be determined, click "Cannot be determined