Use the standard reduction potentials below to determine E°cell for the following reaction under acidic conditions. 4H+(aq) +MnO 2​(s) +2Fe2+(aq) Mn2+(aq) +2Fe3+(aq) +2H 2 ​O(l)
4H+(aq) +MnO 2 ​(s) +2e− Mn2+(aq) +2H 2 ​O(l) $ E° = 1. 23 V
Fe3+(aq) +e− Fe2+(aq) E° = 0. 770 V