Using the Hill-Huntington method of apportionment, if the lower quotas overfill the available positions, which party will lose a seat first?
1) The party with the smallest critical divisor, where
d=P/√n(n+1)
2) The party with the smallest decimal remainder
3) The party with the smallest geometric mean
4) The party with the smallest critical divisor, where
d=P/√n(n-1)