NO⁻₃(aq)+4H+(aq)+3e⁻→NO(g)+2H₂O(l)E∘=0.96V
ClO₂(g)+e−→ClO₂−(aq)E∘= 0.95V
Cu²⁺(aq)+2e−→Cu(s)E∘= 0.34V
2H⁺(aq)+2e−→H₂(g)E∘= 0.00V
Pb²⁺(aq)+2e−→Pb(s)E∘= −0.13V
Fe²⁺(aq)+2e−→Fe(s)E∘= −0.45V
Part A Use appropriate data to calculate E∘cell for the reaction.
3Cu(s)+2NO⁻₃(aq)+8H+(aq)→3Cu²⁺(aq)+2NO(g)+4H₂O(l)