To find the quantity in moles of aluminum in a 13.2 cm³ block of the metal, we can use the formula: $ \text{moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} $ Given: - Density of aluminum = **2.70 g/cm³** - Volume of the block = **13.2 cm³** - Molar mass of aluminum = **26.98 g/mol** First, calculate the mass of the aluminum block: $ \text{mass} = \text{density} \times \text{volume} = 2.70 \, \text{g/cm³} \times 13.2 \, \text{cm³} = 35.64 \, \text{g} $ Then, calculate the moles of aluminum: $ \text{moles} = \frac{35.64 \, \text{g}}{26.98 \, \text{g/mol}} \approx 1.32 \, \text{moles} $ So, a 13.2 cm³ block of aluminum contains approximately **1.32 moles** of aluminum.