You have 50.0 grams of iron and an excess of oxygen (02). How many grams of iron
(III) oxide can you produce?
a. Write the balanced equation.
4Fe + 302 → 2Fe,03
b. Convert from grams of iron to moles of iron
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c. We can then compare the ratios to see how many moles of oxygen gas we would need and how many moles of iron oxide we would produce.
4Fe
30,
→
2Fe,0,
d. Finally, you can convert from moles of product to grams of product to see how much iron (III)