HELP!
In right △ABC, the right angle is at C, m∠A=30∘, and AC=55√ units.

What is the perimeter of △ABC?

Responses
[tex]3\sqrt{15}[/tex]+[tex]5\sqrt{5}[/tex]

[tex]5\sqrt{15}[/tex]+[tex]5\sqrt{5}[/tex]

[tex]3\sqrt{15}+10\sqrt{5}[/tex] / 2

[tex]15\sqrt{15}+10\sqrt{5}[/tex] / 2