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The angle bisectors of AABC are AV, BV, and CV. They meet at a single point V.
(In other words, V is the Incenter of AABC.)
Suppose TV 22, CV = 27, m/ TCU 52°, and mZ SAV=46°.
Find the following measures.
Note that the figure is not drawn to scale.

mASAU =
mASBV =
SV =

The angle bisectors of AABC are AV BV and CV They meet at a single point V In other words V is the Incenter of AABC Suppose TV 22 CV 27 m TCU 52 and mZ SAV46 Fi class=


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