Consider the router and the three attached subnets below (A, B, and C). The number of hosts is also shown below. The subnets share the 23 high-order bits of the address space: 172.17.218.0/23 B A 172.17.218.0/23 hosts 122 hosts 47 hosts 18 What is the subnet address of subnet A and B? (CIDR notation) Sol: Subnet A has 122 hosts, so it will need at least 124 addresses (for the subnet ID and broadcast address). The least number of bits that satisfy this is 7 bits. Knowing that, we take the prior subnet and add 128, the result of which is 172.17.218.0/25 Similar to the prior subnet, subnet B has 47 hosts, so it will need at least 49 addresses (for the subnet ID and broadcast address). The least number of bits that satisfy this is 6 bits. Knowing that, we take the prior subnet and add 64, the result of which is 172.17.218.128/26