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  • 03-05-2024
  • Mathematics
Answered

Find the exact values of sin2v and cos2v

sinv=-5/13, 3pi/2
a) sin2v = 120/169, cos2v= 119/169

b) sin2v= -60/169, cos2v= -120/169

c) sin2v= 60/169, cos2v= 23/13

d) sin2v= -120/169, cos2v= 119/169

e) sin2v= 23/13, cos2v= 288/169



Answer :

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