Using the identity sine, squared, theta, plus, cosine, squared, theta, equals, 1sin
2
θ+cos
2
θ=1, find the value of sine, thetasinθ, to the nearest hundredth, if cosine, theta, equals, minus, 0, point, 5, 8cosθ=−0.58 and start fraction, pi, divided by, 2, end fraction, is less than, theta, is less than, pi
2
π
<θ<π.
Answer