Calculate the Δ H ∘ 298 for the equation: N 2 (g) + 2 O 2 (g) ⟶ 2 NO 2 (g) Use the equations below to help you calculate your answer: Step 1: N 2 (g) + O 2 (g) ⟶ 2 NO (g) Δ H ∘ 298 = 180.5 kJ/mol Step 2: NO (g) + 1 2 O 2 (g) ⟶ NO 2 (g) Δ H ∘ 298 = − 57.06 kJ/mol