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Given the following data:
2NH3(g) + 3N2O(g) -> 4N2(g) + 3H2O(l) ΔH° = -1010 kJ
3H2(g) + N2O(g) -> N2H4(l) + H2O(l) ΔH° = -317 kJ
2NH3(g) + ½O2(g) -> N2H4(l) + H2O(l) ΔH° = -143 kJ
H2(g) + ½O(g) -> H2O(l) ΔH° =-286 kJ

Calculate the ΔH for the following reaction:
N2H4(l) + O2(g) -> N2(g) + 2H2O(l)



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