Given the chemical reaction: KClO₃ = KCl + O₂(g) You have a total volume of 8.3 liters. If you react 60 grams of KClO₃ over water at 36C, what would be the total pressure of the container? What would be the number of grams of water vapor in the container? If the volume of the container stays the same and the amount of KCl₃ stays the same, at what temperature would you have to heat this container to double the number of grams of water in vapor form? Do you have enough information to solve this new temperature? Explain your answer.

show work for like