Reaction 1 and Reaction 2 can be described by the following equations:

Reaction 1: NaOH(s)

→

Na
+
(aq) + OH
−
(aq)

Reaction 2: NaOH(s) + H
+
(aq) + Cl
–
(aq)
→
Na
+
(aq) + Cl
–
(aq) + H
2
O(l)

Multiply, divide, or reverse these equations until they can cancel out and add together to produce the following, which describes Reaction 3:

Reaction 3: Na
+
(aq) + OH
–
(aq) + H
+
(aq) + Cl
–
(aq)
→
Na
+
(aq) + Cl
–
(aq) + H
2
O(l)

Write out on a piece of paper how the first two reactions add up to equal the third, making sure to cross out the cancelled terms. Note that spectator ions (species that do not participate in the reaction) are present; your final answer may be written with or without them. Upload an image showing how the equations are added to equal Reaction 3 into Image 1. Based on how you manipulated Reactions 1 and 2, write out in this answer field a statement that describes how their corresponding ΔH values add to equal ΔH3. Use the following format:
±
n

Δ
H
1

±

n

Δ
H
2
=
Δ
H
3

where n is any integer or fraction the equations were multiplied by, and (+/–) is chosen based on whether the reaction is as written above (ΔH would be positive) or is reversed (ΔH would be negative).