maddysanchez568 maddysanchez568
  • 13-05-2024
  • Chemistry
Answered

2CIF(g) + 02(g) → C1,0(g) + F,°(g)
2CIF (g) + 202(g) → C1,0(g) + 3F,0(g)
2F, (g) + 02(g) → 2F,°(g)
ДН°
rn = 167.4 kJ/mol
ДН°rn = 341.4 kJ/mol
ДН°
rxn
= -43.4 kJ/mol
At the same temperature, use Hess's law to calculate AHn for the reaction:
CIF(g) + F,(g) → CIF (g)



Answer :

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