In circle KK, m, angle, L, K, J, equals, 88, degreesm∠LKJ=88 ∘ . Solve for xx if m, arc, L, J, equals, left bracket, 3, x, minus, 29, right bracket, degreesm LJ ⌢ =(3x−29) ∘ . If necessary, round your answer to the nearest tenth.