During isobaric process m = 30 30 * N/100 kg of wet steam at temperature t = 262.7°C and pressure p= 49 bar changed its specific volume from Vi = v'* (1.1 N/200) m²/kg to V2 = 0" * (0.9 N/200) m²/kg. Find initial and final quality of steam, change of internal energy of steam, work done by steam, amount of heat exchanged with surroundings and change of entropy of steam. Draw the process at the enthalpy-entropy diagram. From tables for p = 49 bar: specific heat of saturated water cw = 4.37 kJ/kg/K, specific volume of saturated water v' = 0.0013 m3/kg, specific volume of saturated vapour u” = 0.0403 m®/kg, specific enthalpy of saturated vapour h” = 2794.7 kJ/kg, specific entropy of saturated vapour S" = 5,983 kJ/kg/K. N is equal to the last two digitals in your student's ID number. N=93