She sees that x = 2 is not a solution because LIS RHS. Next, she tries x = 5 1.11 Determine whether x = 5 is a solution for this equation. 1.1.2. What does she note is different about the LHS and RHS compared to the LHS and RHS in her first attempt? 1.1.3. Would it make sense to try an x - value between 2 and 5 as her next attempt? 1.1.4 Find the correct solution by using algebraic methods. (2 (2 (4​