A reaction proceeds with 2.72 moles of magnesium chlorate and 3.14 moles of sodium hydroxide. This is the equation of the reaction: Mg(ClO_3)_2+2NaOHto Mg(OH)_2+2NaClO_3. Determine the theoretical amount of each product that the reaction will produce. The reaction will produce □ of magnesium hydroxide and □ of sodium chlorate. 1.36 moles Reset Next 1.57 moles 2. 72 moles 3. 14 moles 4. 52 moles