The figure below shows a charged particle, with a charge of q = +39.0 nC, that moves a distance of d = 0.177 m from point A to point B in the presence of a uniform electric field E of magnitude 295 N/C, pointing right. A positive point charge q is initially at point A, then moves a distance d to the right to point B. Electric field vector E points to the right. (a) What is the magnitude (in N) and direction of the electric force on the particle? magnitude 11.5 N direction toward the right (b) What is the work (in J) done on the particle by the electric force as it moves from A to B? 2.04 J (c) What is the change of the electric potential energy (in J) as the particle moves from A to B? (The system consists of the particle and all its surroundings.) PEB − PEA = J