How much heat (in kJ ) is required to convert 111g of solid water at -125.0°C to water vapor at 125°C.
Hint: You will need five equations that you add together because the water is a liquid.
Tip 1: Three equations use m and the other two use n.n is moles. m is mass in grams. You should put the final units for both in terms of grams.
Tip 2: One equation will come out in J. One will come out in kJ. You have to put them both in kJ before you can add them.
Values that may be needed for this problem.
Δ Hvap (H₂O,100°C) = 43.9 kJmol
Δ Hfus (H₂O,0°C) = 6.02 kJmol
Cᵢₑ = 2.09J/(g*C)
cₐₜₑᵣ = 4.184J/(g*C)
cᵥₐₚ (H₂O) = 1.84J/(g*C)