A box contains four red balls and eight black balls. Two balls are randomly chosen from the box, and are not replaced. Let event B be choosing a black ball first and event R be choosing a red ball second. What are the following probabilities? P(B) = 8/12 P(R | B) = 4/12 P(B ∩ R) = The probability that the first ball chosen is black and the second ball chosen is red is about percent.