Which is the solution of the quadratic equation (4y – 3)2 = 72?

y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction and y = StartFraction 3 minus 6 StartRoot 2 EndRoot Over 4 EndFraction
y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction and y = StartFraction negative 3 minus 6 StartRoot 2 EndRoot Over 4 EndFraction
y = StartFraction 9 StartRoot 2 EndRoot Over 4 EndFraction and y = StartFraction negative 3 StartRoot 2 EndRoot Over 4 EndFraction
y = StartFraction 9 StartRoot 2 EndRoot Over 4 EndFraction and y = StartFraction 3 StartRoot 2 EndRoot Over 4 EndFraction