LayLay41531 LayLay41531 05-06-2024 Mathematics Answered Solve the following differential equation.(dy)/(dt) + (2ty)/(1+t²) = 4tya) y = ((2t² + (4/3)t⁶ + C) / (1 + t²)²)b) y = ((2/3)(1 + t²)³ + C) / (1 + t²)²c) y = (1(1 + t²)² + C) / (1 + t²)d) y = ((4/3)t⁶ + C) / (1 + t²)