Answer :
The reason for statement 3 in this proof is:
E. definition of midpoint
Statement 3 gives the coordinates of points [tex]\(D\)[/tex] and [tex]\(E\)[/tex], which are midpoints of line segments [tex]\(\overline{AB}\)[/tex] and [tex]\(\overline{BC}\)[/tex], respectively. According to the definition of a midpoint, the coordinates of a midpoint are the averages of the coordinates of the endpoints of the line segment.
- For point [tex]\(D\)[/tex], which is the midpoint of [tex]\(\overline{AB}\)[/tex], the coordinates are calculated as [tex]\(\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)\)[/tex].
- For point [tex]\(E\)[/tex], which is the midpoint of [tex]\(\overline{BC}\)[/tex], the coordinates are calculated as [tex]\(\left(\frac{x_2+x_3}{2}, \frac{y_2+y_3}{2}\right)\)[/tex].
Therefore, the coordinates given in statement 3 align with the definition of a midpoint.
E. definition of midpoint
Statement 3 gives the coordinates of points [tex]\(D\)[/tex] and [tex]\(E\)[/tex], which are midpoints of line segments [tex]\(\overline{AB}\)[/tex] and [tex]\(\overline{BC}\)[/tex], respectively. According to the definition of a midpoint, the coordinates of a midpoint are the averages of the coordinates of the endpoints of the line segment.
- For point [tex]\(D\)[/tex], which is the midpoint of [tex]\(\overline{AB}\)[/tex], the coordinates are calculated as [tex]\(\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)\)[/tex].
- For point [tex]\(E\)[/tex], which is the midpoint of [tex]\(\overline{BC}\)[/tex], the coordinates are calculated as [tex]\(\left(\frac{x_2+x_3}{2}, \frac{y_2+y_3}{2}\right)\)[/tex].
Therefore, the coordinates given in statement 3 align with the definition of a midpoint.