Explain why CH₃CH₂CH₂Br is not formed during the radical bromination of CH₃CH₂CH₃.

A. Due to the electron-withdrawing properties of halides, the compound will immediately decompose to a double bond.
B. Benzylic radicals are much more stable than primary radicals.
C. Under these conditions the bromine will add to the ortho or para position of the benzene ring.
D. Radical halogenation forms the kinetic product rather than the thermodynamic product.