In the figure below, a broad beam of light of wavelength 520 nm is incident at 90° on a thin, wedge-shaped film with index of refraction 1.45.
Transmission gives 13 bright and 12 dark fringes along the film's length. What is the left-to-right change in film thickness? Answer in m. Please help!

Question

05-07-2024
Physics

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In the figure below, a broad beam of light of wavelength 520 nm is incident at 90° on a thin, wedge-shaped film with index of refraction 1.45.
Transmission gives 13 bright and 12 dark fringes along the film's length. What is the left-to-right change in film thickness? Answer in m. Please help!

$In the figure below a broad beam of light of wavelength 520 nm is incident at 90 on a thin wedgeshaped film with index of refraction 145 Transmission gives 13 b class=$

Answer :

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In the figure below, a broad beam of light of wavelength 520 nm is incident at 90° on a thin, wedge-shaped film with index of refraction 1.45. Transmission gives 13 bright and 12 dark fringes along the film's length. What is the left-to-right change in film thickness? Answer in m. Please help!

Answer :

Other Questions

In the figure below, a broad beam of light of wavelength 520 nm is incident at 90° on a thin, wedge-shaped film with index of refraction 1.45.
Transmission gives 13 bright and 12 dark fringes along the film's length. What is the left-to-right change in film thickness? Answer in m. Please help!