Rewrite the following equation so that it equals zero on one side:
[tex]\[ 2^2 - 4 = 5^{-} - 2 \][/tex]

Follow these steps for the first iteration:

\begin{tabular}{|c|c|}
\hline
Step 1 & \begin{tabular}{l}
Rewrite the equation so that it equals zero on one side. \\
[tex]\[ (2^2 - 4) - (3^{-} - 2) = 0 \][/tex]
\end{tabular} \\
\hline
Step 2 & \begin{tabular}{l}
Evaluate the rewritten equation at the lower and upper bounds. \\
To find the solution that lies between 1 and 2, set these values \\
as the lower and upper bounds while finding the root twice. \\
[tex]\[ (2^{1} - 4) - (3^{-1} - 2) \approx -0.333 \][/tex] \\
[tex]\[ (2^{2} - 4) - (3^{-1} - 2) \approx 1.889 \][/tex]
\end{tabular} \\
\hline
Step 3 & \begin{tabular}{l}
Take the average of the lower and upper bounds. \\
[tex]\[ \frac{1+2}{2} = \frac{3}{2} \][/tex]
\end{tabular} \\
\hline
Step 4 & \begin{tabular}{l}
Evaluate the rewritten equation at [tex]\( x = \frac{3}{2} \)[/tex]. \\
[tex]\[ (2(\frac{3}{2}) - 4) - (3(\frac{1}{2}) - 2) \approx 0.636 \][/tex]
\end{tabular} \\
\hline
Step 5 & \begin{tabular}{l}
Since this value is positive, replace the previous lower bound so that \\
the bounds are now [tex]\( x = \frac{1}{2} \)[/tex] and [tex]\( x = 2 \)[/tex].
\end{tabular} \\
\hline
\end{tabular}

Where did Jacob make a mistake and what was the error?