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  • 24-07-2024
  • Physics
Answered

A thin-walled sphere of mean diameter D has a wall thickness of t. It is subjected to an internal pressure of p. Show that the change in volume (ΔV) and change in diameter (ΔD) are:
ΔV = (3pDV / 4tE) (1 - v) where V is the initial volume.



Answer :

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