An electron moves across Earth's equator at a speed of 2.46×10⁶ m/s and in a direction 30.0ºN of E. At this point, Earth's magnetic field has a direction due north, is parallel to the surface, and has a magnitude of 0.233×10⁻⁴ T. What is the magnitude of the force acting on the electron due to its interaction with Earth's magnetic field?