Use the compound interest formulas [tex]A = P(1 + \frac{r}{n})^{nt}[/tex] and [tex]A = Pe^{rt}[/tex] to solve the problem. Round answers to the nearest cent.

Find the accumulated value of an investment of [tex]$15,000 for 5 years at an interest rate of 5% if the money is:
a. Compounded semiannually
b. Compounded quarterly
c. Compounded continuously

a. What is the accumulated value if the money is compounded semiannually?
(Round your answer to the nearest cent. Do not include the $[/tex] symbol in your answer.)



Answer :

To find the accumulated value of an investment of [tex]$15,000 over 5 years at an interest rate of 5%, we use the compound interest formulas \( A = P \left(1 + \frac{r}{n}\right)^{nt} \) for periodic compounding and \( A = Pe^{rt} \) for continuous compounding. Given: - Principal amount, \( P \) = $[/tex]15,000
- Annual interest rate, [tex]\( r \)[/tex] = 5% or 0.05
- Time, [tex]\( t \)[/tex] = 5 years

We solve the problem for three types of compounding: semiannual, quarterly, and continuous.

### a. Compounded Semiannually
For semiannual compounding:
- Compounding frequency, [tex]\( n \)[/tex] = 2 (since it is compounded twice a year)

The formula to use is:
[tex]\[ A = P \left(1 + \frac{r}{n}\right)^{nt} \][/tex]

Plugging in the numbers:
[tex]\[ A = 15000 \left(1 + \frac{0.05}{2}\right)^{2 \cdot 5} \][/tex]
[tex]\[ A = 15000 \left(1 + 0.025\right)^{10} \][/tex]
[tex]\[ A = 15000 \left(1.025\right)^{10} \][/tex]

After calculating the expression:
[tex]\[ A \approx 19201.27 \][/tex]

Therefore, the accumulated value if the money is compounded semiannually is:
[tex]\[ \boxed{19201.27} \][/tex]

### b. Compounded Quarterly
For quarterly compounding:
- Compounding frequency, [tex]\( n \)[/tex] = 4 (since it is compounded four times a year)

The formula to use is:
[tex]\[ A = P \left(1 + \frac{r}{n}\right)^{nt} \][/tex]

Plugging in the numbers:
[tex]\[ A = 15000 \left(1 + \frac{0.05}{4}\right)^{4 \cdot 5} \][/tex]
[tex]\[ A = 15000 \left(1 + 0.0125\right)^{20} \][/tex]
[tex]\[ A = 15000 \left(1.0125\right)^{20} \][/tex]

After calculating the expression:
[tex]\[ A \approx 19230.56 \][/tex]

Therefore, the accumulated value if the money is compounded quarterly is:
[tex]\[ \boxed{19230.56} \][/tex]

### c. Compounded Continuously
For continuous compounding:
The formula to use is:
[tex]\[ A = Pe^{rt} \][/tex]

Plugging in the numbers:
[tex]\[ A = 15000 \times e^{0.05 \cdot 5} \][/tex]

Since [tex]\( e \)[/tex] is a mathematical constant approximately equal to 2.71828:
[tex]\[ A = 15000 \times e^{0.25} \][/tex]
[tex]\[ A = 15000 \times 1.284025 \][/tex]

After calculating the expression:
[tex]\[ A \approx 19260.38 \][/tex]

Therefore, the accumulated value if the money is compounded continuously is:
[tex]\[ \boxed{19260.38} \][/tex]

In summary:
- Compounded semiannually: [tex]\( 19201.27 \)[/tex]
- Compounded quarterly: [tex]\( 19230.56 \)[/tex]
- Compounded continuously: [tex]\( 19260.38 \)[/tex]