Type the correct answer in each box. Use numerals instead of words.

A company manufactures 2,000 units of its flagship product in a day. The quality control department takes a random sample of 40 units to test for quality. The product is put through a wear-and-tear test to determine the number of days it can last. If the product has a lifespan of less than 26 days, it is considered defective. The table gives the sample data that a quality control manager collected.

\begin{tabular}{|l|l|l|l|l|}
\hline 39 & 31 & 38 & 40 & 29 \\
\hline 32 & 33 & 39 & 35 & 32 \\
\hline 32 & 27 & 30 & 31 & 27 \\
\hline 30 & 29 & 34 & 36 & 25 \\
\hline 30 & 32 & 38 & 35 & 40 \\
\hline 29 & 32 & 31 & 26 & 26 \\
\hline 32 & 26 & 30 & 40 & 32 \\
\hline 39 & 37 & 25 & 29 & 34 \\
\hline
\end{tabular}

The point estimate of the population mean is [tex]$\square$[/tex] and the point estimate of the proportion of defective units is [tex]$\square$[/tex].



Answer :

To solve this problem, follow these detailed steps:

1. Identify the Sample Data:
The sample data provided consists of 40 units with the following lifespans (in days):
```
[39, 31, 38, 40, 29, 32, 33, 39, 35, 32, 32, 27, 30, 31, 27,
30, 29, 34, 36, 25, 30, 32, 38, 35, 40, 29, 32, 31, 26, 26,
32, 26, 30, 40, 32, 39, 37, 25, 29, 34]
```

2. Calculate the Point Estimate of the Population Mean:
To find the point estimate of the population mean, you compute the mean (average) of the sample data:
[tex]\[ \text{Population Mean Estimate} = \text{Mean} = \frac{\sum{x}}{n} \][/tex]
where [tex]\( x \)[/tex] is each individual lifespan value, and [tex]\( n \)[/tex] is the number of samples (40 in this case).

After performing the calculation, the point estimate of the population mean is:
[tex]\[ 32.3 \][/tex]

3. Determine the Threshold for Defectiveness:
A product is considered defective if its lifespan is less than 26 days.

4. Calculate the Proportion of Defective Units:
To calculate the proportion of defective units, count how many units have a lifespan of less than 26 days and divide it by the total number of units (40):
[tex]\[ \text{Proportion of Defective Units} = \frac{\text{Number of Defective Units}}{n} \][/tex]
After counting, there are 2 units with a lifespan of less than 26 days out of the 40 units.

The proportion of defective units is:
[tex]\[ 0.05 \][/tex]

Thus, the point estimate of the population mean is [tex]\( 32.3 \)[/tex] and the point estimate of the proportion of defective units is [tex]\( 0.05 \)[/tex].

So, the final answer is:

The point estimate of the population mean is [tex]\( 32.3 \)[/tex] and the point estimate of the proportion of defective units is [tex]\( 0.05 \)[/tex].