The reaction 2NOBr -> 2NO+ Br₂
exhibits the rate law
R=k[NOBr]² = -Δ[NOBr]/Δt
where k = 0.769 M⁻¹ ⋅ s⁻¹ at 25°C. This reaction is run where the initial concentration of NOBr ([NOBr]₀) is 1.00 × 10⁻¹ M.
The [NO] after 1.00 hour has passed is:
- 3.6 × 10⁻⁴ M
- 9.9 × 10⁻³ M
- 9.7 × 10⁻³ M
- 1.0 × 10⁻³ M
- None of these