Here’s a step-by-step breakdown for each reactant:
1. Copper(II) chloride (CuCl[tex]\(_2\)[/tex]):
- Given mass of CuCl[tex]\(_2\)[/tex]: 2.50 grams - Molar mass of CuCl[tex]\(_2\)[/tex]: 134.45 grams per mole
Using the formula: [tex]\[
\text{moles of CuCl}_2 = \frac{2.50 \text{ grams}}{134.45 \text{ grams per mole}}
\][/tex] [tex]\[
\text{moles of CuCl}_2 \approx 0.0186 \text{ moles}
\][/tex]
Rounding to 2 significant figures: [tex]\[
\text{moles of CuCl}_2 \approx 0.02 \text{ moles}
\][/tex]
2. Aluminum (Al):
- Given mass of Al: 0.25 grams - Molar mass of Al: 26.98 grams per mole
Using the formula: [tex]\[
\text{moles of Al} = \frac{0.25 \text{ grams}}{26.98 \text{ grams per mole}}
\][/tex] [tex]\[
\text{moles of Al} \approx 0.00927 \text{ moles}
\][/tex]
Rounding to 2 significant figures: [tex]\[
\text{moles of Al} \approx 0.01 \text{ moles}
\][/tex]
Thus, the conversions are: [tex]\[
2.50 \text{ g of CuCl}_2 \text{ equals } 0.02 \text{ moles}
\][/tex] [tex]\[
0.25 \text{ g of Al equals } 0.01 \text{ moles}
\][/tex]
