seagleD3187 seagleD3187 13-08-2024 Chemistry Answered What is the pH of a solution of 0.149 M CH₃NH₂ and 0.178 M CH₃NH₃Cl? CH₃NH₂(aq) + H₂O(l) = CH₃NH₃(aq) + OH(aq) Kb = 4.4 x 10⁻⁴.