Lukew40821 Lukew40821 13-08-2024 Mathematics Answered Solve the equations for solutions in the interval [0º, 360º). Round to the nearest degree. sin 2θ= -1/2 A. {15º, 165º, 195º, 345º} B. {30º, 90º, 150ª, 270º}C. {105º, 165º, 285º, 345º}D. {0º, 120º, 180º, 240º}