Answer :

x ²+2x-15

factorize the equation

(x+5)(x-3)

therefore the zeros are -5 and 3
[tex]f(x)=x^2+2x-15\\\\f(x)=0\iff x^2+2x-15=0\\\\x^2+5x-3x-15=0\\\\x(x+5)-3(x+5)=0\\\\(x+5)(x-3)=0\iff x+5=0\ or\ x-3=0\\\\\boxed{x=-5\ and\ x=3}\leftarrow zeros[/tex]