Answer :

[tex]-2(3y+5)=-4\\\\-6y-10=-4\ \ \ \ \ |add\ 10\ to\ both\ sides\\\\-6y=6\ \ \ \ \ \ |divide\ both\ sides\ by\ (-6)\\\\\boxed{y=-1}[/tex]
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konrad509
[tex]-2(3y+5)=-4\\ -6y-10=-4\\ -6y=6\\y=-1\\\\ 5y=5\cdot(-1)=-5[/tex]