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Gabriella wants to tile a room with an area of 320 square feet. The width of the room is 4/5 its length. What are the length and width of the room?



Answer :

mackiemesser
lenght - a
width - b
Area= a*b
320=ab
b=4/5a
320=[tex] 4a^{2}/5[/tex]
400=[tex] a^{2} [/tex]
a=[tex] \sqrt{400} [/tex]
a=20
b=16
repraiseds

Answer:

Read below.

Step-by-step explanation:

A=l*w

320=l*(4/5)l

320=(4/5)(l2)

(5/4)(320)=(5/4)(4/5)(l2)

5(80)=l2   (320/4=80)

400=l2

√400=√l2

20=l

w=(4/5)(20)

w=4*4  (20/5=4)

w=16

length=20 feet

width=16 feet

If you don't understand square roots, maybe you understand prime factorization.

320=2*2*2*2*2*2*5=(2*2*2*2)*(2*2*5)=16*20 and 16 is 4/5 of 20

If you don't understand prime factorization you can use trial and error.

2*160

4*80

5*64

8*40

10*32

16*20  answer, because 16 is 4/5 or 0.8 times 20

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