Coulomb's Law:
[tex]F=\frac{kq_1q_2}{r^2}[/tex]
k is a constant
q1 and q2 are charges
r is the distance
[tex]F_1=\frac{kq_1q_2}{r^2}[/tex]
the distance is tripled:
[tex]F_2=\frac{kq_1q_2}{(3r)^2}=\frac{kq_1q_2}{9r^2}[/tex]
[tex]\frac{\frac{kq_1q_2}{9r^2}}{\frac{kq_1q_2}{r^2}}= \frac{r^2}{9r^2}=\frac{1}{9}[/tex]
The strength of the electrostatic repulsion will decrease by a factor of 9.
