Answer :
[tex]x-\ number\ of\ adults\\\\
(x+477)-\ number\ of\ students\\\\
Ratio:\\
\frac{adults}{students}=\frac{1}{10}\\
\frac{x}{x+477}=\frac{1}{10}\\
10x=x+477\\
10x-x=477\\9x=477\ \ \ |:9\\x=53.\\\\There\ will\ be\ 53\ adults\ at\ the\ prom.[/tex]