Answer :
To answer this problem, we have to employ Newton's Second Law of Motion, or F = ma. F is the force in Newtons (N) where as m is mass (kg) and a is the acceleration (m/s^2). An easy plug in will give us
F = ma
F = (40,000 kg.)(0.9 m/s^2)
F = 36,000 N.
The answer is 36,000 N. Good luck!
F = ma
F = (40,000 kg.)(0.9 m/s^2)
F = 36,000 N.
The answer is 36,000 N. Good luck!
The net force acting on the subway car and it's passengers is 3.6 × 10⁴ Newton.
Given the data in the question;
- Mass of a subway car and it's passengers; [tex]m = 40000 kg[/tex]
- Acceleration as it leaves the station; [tex]a = 0.9 m/s^2[/tex]
Net force; [tex]F = \ ?[/tex]
From Newton's second law of Motion:
[tex]F = m\ *\ a[/tex]
Where F is the force, m is mass of object and a is the acceleration.
We substitute our given values into the equation
[tex]F = 40000kg\ *\ 0.9m/s^2\\\\F = 36000 kg.m/s^2\\\\F = 3.6*10^4N[/tex]
Therefore, the net force acting on the subway car and it's passengers is 3.6 × 10⁴ Newton.
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