10-09-2014
Physics

Answered

Starting at a certain speed, a bicyclist travels 200m. Suppose the bicyclist undergoes a constant acceleration of 1.20m/s squared. If the final speed is 25.0m/s, what was the bicyclists initial speed?

Answer :

11-09-2014

V2^2 = V1^2 + 2*a* s
V2 = final velocity
V1 = initial velocity
a = acceleration
s = displacement covered
25^2 = V1^2 + 2 * 1.2 * 200
625 = V1^2 + 480
625 - 480 = V1^2
145 = V1^2
So V1 = Sqrt(145) = 12.04 m/s

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