Answer :
Convert all the mL to L first, .25 L and .84 L (.25) (.5) = (.84) (x) solve... I got .148809524, round to one sig fig (i think) would be .1 M
Answer: a) 0.15 M
Explanation:
According to the dilution law,
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1[/tex] = molarity of stock solution = 0.50 M
[tex]V_1[/tex] = volume of stock solution = 250 ml
[tex]M_2[/tex] = molarity of diluted solution = ?
[tex]V_2[/tex] = volume of diluted solution = 840 ml
Putting in the values, we get:
[tex]0.50M\times 250=M_2\times 840[/tex]
[tex]M_2=0.15[/tex]
Therefore, the molarity of the resulting solution is 0.15 M